One mole of an ideal gas will occupy a volume of 22.4 liters at STP (Standard Temperature and Pressure, 0°C and one atmosphere pressure).
Proportion:
1 mole – 22.4 L
n moles – 2.75 L
"n = \\frac{1 \\times 2.75}{22.4} = 0.122 \\;mol"
Answer: 0.122 mol
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