One mole of an ideal gas will occupy a volume of 22.4 liters at STP (Standard Temperature and Pressure, 0°C and one atmosphere pressure).
Proportion:
1 mole – 22.4 L
n moles – 2.75 L
n=1×2.7522.4=0.122 moln = \frac{1 \times 2.75}{22.4} = 0.122 \;moln=22.41×2.75=0.122mol
Answer: 0.122 mol
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