Question

C6H12O6 = 2C2H5OH + 2CO2

If 3.44 mol of ethanol are produced during the reaction, how many mol of glucose have been used?

Answer 1

Given chemical reaction,

C6H12O6 = 2C2H5OH + 2CO2

From the above reaction,

2 mole of ethanol are produced from 1 mole glucose

1 moles of ethanol are produced from

(1/2) mole glucose

3.44 moles of ethanol are produced

from (1/2)×3.44 mole glucose

= 1.72 mole

Hence,

If 3.44 mol of ethanol are produced during the reaction, then 1.72 mole of glucose have been used.