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Answer to Question #145320 in General Chemistry for Kww

Question #145320
What mass of KI is required to make 500. mL of a 2.80 M KI solution?
1
Expert's answer
2020-11-20T09:59:36-0500


(500ml)(1L/1000ml) =(5/40)L


(5/10L)(2.80 mol KI/ 1L soln) (166g KI/ 1mol KI) = 232g KI



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