Answer to Question #145320 in General Chemistry for Kww

Question #145320

What mass of KI is required to make 500. mL of a 2.80 M KI solution?

Expert's answer

(500ml)(1L/1000ml) =(5/40)L

(5/10L)(2.80 mol KI/ 1L soln) (166g KI/ 1mol KI) = 232g KI

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