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Answer to Question #145320 in General Chemistry for Kww
Question #145320
What mass of KI is required to make 500. mL of a 2.80 M KI solution?
Expert's answer
(500ml)(1L/1000ml) =(5/40)L
(5/10L)(2.80 mol KI/ 1L soln) (166g KI/ 1mol KI) = 232g KI
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