σ\sigmaσ f= 3p2/2bd2
Hence P=2bd2 σ\sigmaσf/3L
PA=2×2.5×(0.5)2×σ×2.5×(0.5)2× \sigma×2.5×(0.5)2×σf/ 3×1.53×1.53×1.5
PA=0.33PA=0.33PA=0.33σ\sigmaσf
PB=2×1.5×(0.75)2×σPB=2×1.5×(0.75)2×\sigmaPB=2×1.5×(0.75)2×σf/3×1.53×1.53×1.5
=0.38σ=0.38\sigma=0.38σ f
=0.38σ=0.38\sigma=0.38σ f>PA(0.33)σ>PA(0.33)\sigma>PA(0.33)σf
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