Answer to Question #144799 in General Chemistry for Abigail Nicole Cruz

Question

Calculate the amount of heat required to convert 10.0 grams of ice at -20.°C to steam at 120.°C. (Sp. heat of H2O(s) = 2.09 J/g•°C, Sp. heat of H2O( ) = 4.18 J/g•°C, Sp heat of H2O(g) = 2.03 J/g•°C; heat of fus. of H2O(s) = 333 J/g, heat of vap. of H2O( ) = 2260 J/g)
a. 18.6 kJ
b. 26.3 kJ
c. 30.9 kJ
d. 41.2 kJ
e. 46.4 kJ

Answer 1

Q=mc∆T.

Q1= 10 x 2.09 x 0-(-20) = 418.

Q2= 10 x 4.18 x 100 = 4180.

Q3=10 x 2.03 x 20 = 406.

e.