CxHyOz+O2⟺CO2+H2O
m(CxHyOz)= 19.81 mg
m(CO2) = 41.68 mg
m(H2O) = 6.45 mg
44−41.68mg
12−x=11.3672mg
18−6.45mg
2−x=0.7167g
m(oxygen) = m(terephtgalic acid) - m(carbon) - m(hydrgen) = 7.7261mg
(CxHyOz)=1211.3672=10.7167=167.7261= 0.9472647:0.7167:0.48288125
n(CxHyOz)=166g = 166g
41n=166g
n=4
C8H6O4
C4H3O2
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