Answer to Question #144774 in General Chemistry for Joshua

Question

150 kg of propane is burned with 35% excess air . 85% of the carbon in the fuel burns to CO2 and the remaining to CO. Find the complete analysis of the flue gas.

Answer 1

Propane is C₃H₈

since 44 g of propane contains 36 g Carbon.

so in 150 kg it contains 122.73 kg carbon.

out of which 85% is responsible for CO₂ .

104.32 kg carbon or 127.5 Kg propane is responsible for CO₂

C₃H₈ + 5 O₂ $\rightarrow$ 3CO₂ + 4 H₂O

1mole of propane gives 3 moles of CO₂

127.5 Kg propane is equal to 2.89 Kmoles

so it will give 383.50 Kg of CO₂

C₃H₈ + (7/2) O₂ $\rightarrow$ 3CO + 4H₂O

so remaining 22.5 Kg propane will produce CO.

22.5 Kg is responsible for 42.95 Kg CO.