Mr(NH3) = Ar(N) + 3*Ar(H) = 14 g/mol + 3*1 g/mol = 17 g/mol
n(NH3) = m(NH3)/Mr(NH3) = (10 g)/(17 g/mol) = 0.5882 mol
n(H2) = n(NH3)*3/2 (stoichiometry coefficients)
n(H2) = (0.5882 mol)*3/2 = 0.8823 mol
m(H2) = n(H2)*Mr(H2) = 2*n(H2)*Ar(H) = 2*(0.8823 mol)*(1 g/mol) = 1.7646 g
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