Molar mass C7H8 = 92.14 g/mol
Molar mass KC7H5O2 = 160.21 g/mol
Percent yield = Actual yield/Theoretical yield × 100%
Theoretical yield of KC7H5O2 = actual yield/percent yield × 100% = 11.4g/65% × 100% = 17.54 g KC7H5O2
According to the reaction equation from 1 mol of C7H8 be produced 1 mole of KC7H5O2.
Mass of C7H8 = 17.54g KC7H5O2/160.21g/mol KC7H5O2 × 92.14g/mol C7H8 = 10.09 g C7H8
Answer: mass of C7H8 is 10.09 grams.
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