Question

Calculate the volume (in liters) occupied by 2.12 moles of nitric oxide (NO) at 6.54 atm and 76°C.

Answer 1

Solution:

$PV = nRT$

$V= \dfrac{nRT}{P}$

$V= \dfrac{(2.12 moles)(0.0821( \tfrac{L*atm}{mol*K})(349K) }{(6.54atm)}$

$V=9.3 L$