V1=400ccP1=740mmHgT1=18°C=18+273K=291KV2=?P2=760mmHgT2=0°C=0+273K=273K\begin{aligned} V_1 &= 400cc\\ P_1 &= 740mmHg\\ T_1 &= 18°C = 18 + 273K = 291K\\ \\ V_2 &= ?\\ P_2 &= 760mmHg\\ T_2 &= 0°C = 0 + 273K = 273K \end{aligned}V1P1T1V2P2T2=400cc=740mmHg=18°C=18+273K=291K=?=760mmHg=0°C=0+273K=273K
From, ideal gas law P1V1T1=P2V2T2\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2}T1P1V1=T2P2V2
400×740291=760×V2273\dfrac{400×740}{291} = \dfrac{760×V_2}{273}291400×740=273760×V2
V2=400×740×273760×291V_2 = \dfrac{400×740×273}{760×291}V2=760×291400×740×273
V3=365.38ccV_3 = 365.38ccV3=365.38cc
∴\therefore∴ 365.38cc is the volume of air at 760 mmHg and 0°C.
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