"\\begin{aligned}\nV_1 &= 400cc\\\\\nP_1 &= 740mmHg\\\\\nT_1 &= 18\u00b0C = 18 + 273K = 291K\\\\\n\\\\\nV_2 &= ?\\\\\nP_2 &= 760mmHg\\\\\nT_2 &= 0\u00b0C = 0 + 273K = 273K\n\n\\end{aligned}"
From, ideal gas law "\\dfrac{P_1V_1}{T_1} = \\dfrac{P_2V_2}{T_2}"
"\\dfrac{400\u00d7740}{291} = \\dfrac{760\u00d7V_2}{273}"
"V_2 = \\dfrac{400\u00d7740\u00d7273}{760\u00d7291}"
"V_3 = 365.38cc"
"\\therefore" 365.38cc is the volume of air at 760 mmHg and 0°C.
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