Question #144037
A volume of 400 cc air is measured at a pressure of 740 mmHg and a temperature of 18°C. What will be the volume (in cc) at 760 mmHg and 0°C?
1
Expert's answer
2020-11-12T07:12:07-0500

V1=400ccP1=740mmHgT1=18°C=18+273K=291KV2=?P2=760mmHgT2=0°C=0+273K=273K\begin{aligned} V_1 &= 400cc\\ P_1 &= 740mmHg\\ T_1 &= 18°C = 18 + 273K = 291K\\ \\ V_2 &= ?\\ P_2 &= 760mmHg\\ T_2 &= 0°C = 0 + 273K = 273K \end{aligned}


From, ideal gas law P1V1T1=P2V2T2\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2}


400×740291=760×V2273\dfrac{400×740}{291} = \dfrac{760×V_2}{273}


V2=400×740×273760×291V_2 = \dfrac{400×740×273}{760×291}


V3=365.38ccV_3 = 365.38cc


\therefore 365.38cc is the volume of air at 760 mmHg and 0°C.


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