A sample of CaCl2 weighing 7.45g is dissolved in 10.0mL of water, heated to 80°C then allowed to cool. It begins to crystallize (come out of solution as solid) when it reaches 20°C. Calculate the solubility of CaCl2 in grams/100mL at 20°C
mass dissolved = 7.45g
volume of water = 10.0mL
"\\begin{aligned}\nCaCl_2 \\textsf{ solubility }(g\/100mL) &= \\dfrac{mass(g)}{volume(mL)} \u00d7 100\\\\\n\\\\\n&=\\dfrac{7.45}{10} \u00d7 100\\\\\n\\\\\n&= 74.5\\ g\/100mL\\ at\\ 20\u00b0C\n\\end{aligned}"
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