Question #142527

A sample of CaCl2 weighing 7.45g is dissolved in 10.0mL of water, heated to 80°C then allowed to cool. It begins to crystallize (come out of solution as solid) when it reaches 20°C. Calculate the solubility of CaClin grams/100mL at 20°C 


1
Expert's answer
2020-11-09T13:50:40-0500

mass dissolved = 7.45g

volume of water = 10.0mL


CaCl2 solubility (g/100mL)=mass(g)volume(mL)×100=7.4510×100=74.5 g/100mL at 20°C\begin{aligned} CaCl_2 \textsf{ solubility }(g/100mL) &= \dfrac{mass(g)}{volume(mL)} × 100\\ \\ &=\dfrac{7.45}{10} × 100\\ \\ &= 74.5\ g/100mL\ at\ 20°C \end{aligned}

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