Answer to Question #142508 in General Chemistry for Bruce

Question

Correct combination of numbers and unit/substances from the drop down menus to setup and solve the following problem

how many grams are in 5.32 x 10(24) atoms of neon

Answer 1

A mole of neon atoms (with the formula Ne) contains 6.02×10²³ Ne atoms.

Proportion:

1 mol - 6.02×10²³ Ne atoms

x mol - 5.32×10²⁴ Ne atoms

$x = \frac{5.32 \times 10^{24}}{6.02 \times 10^{23}}$

x = 8.83 mol

M(Ne) = 20.18 g/ mol

m = n×M

m(Ne) = 8.83 × 20.18 = 178.19 g

Answer: 178.19 g