Answer to Question #142376 in General Chemistry for taryn

Question

1.00 mole of Ca and 1.00 more of CL2 were present as reactants. Only 106 g of CaCL2 is Produced. what is the percent yield

Answer 1

Ca + Cl₂ = CaCl₂

1 mole each of reactants produce 1 mole of CaCl₂

m(CaCl₂ ) = n (CaCl₂ ) x M (CaCl₂ )

m(CaCl₂ ) = 1 mol * x 110.98 g/mol = 110.98 g - mass CaCl₂ in theory

the percent yield = (mass in fact/mass in theory)x100% = 106 g / 110.98 g x 100% = 95.5%