Answer to Question #142367 in General Chemistry for iduhc

Question #142367

An atom emits photons of light having a wavelength of 430 nm. What is the energy of the light?

Expert's answer

E=hc/lambda= 6.626 x10^-34 x 3 x 10^8/4.3x10^-7= 4,6227907e-19 J.

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