A. Manipulating the interpreted rate law of zero-order reactions and substituting values,
[A]tk[Ao][A][A][A]=[Ao]−kt=5(60)=300s=0.42M/s=0.084M=0.084−0.42(300)=0.084−126=−125.916M
But since concentration can't be negative, we can safely infer that it's final concentration is 0M.
B. t21t21t21t21=2k[Ao]=2(0.42)0.37=0.840.37=0.44s
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