The general equation for the reaction is;
"Na+O\\to Na_2O"
Mass"=" Moles"\\times" Molar mass.
Moles"=0.5M"
Molar mass of "Na_2O=54.989=54.99"
From the formula;
"\\therefore" Mass"=" "0.5\\times 54.989" "= 27.49g"
The mass of "Na" which reacts"=27.49g"
Number of moles "=" "Mass Of Substance\\over Mass Of One Mole"
Number of moles of "Na=" "27.49\\over 54.989" "=0.499mol"
The number of Moles of Sodium ions formed "=0.49 moles"
Comments
Leave a comment