[Hbr] = 0.25 M
[O2] = 0.25 M
Rate = k[HBr][O2]
6.54×10−3 mol/L s=k(0.25 mol/L)(0.25 mol/L)6.54 \times 10^{-3} \;mol/L\;s = k(0.25 \;mol/L)(0.25 \;mol/L)6.54×10−3mol/Ls=k(0.25mol/L)(0.25mol/L)
k=6.54×10−3 mol/L s(0.25 mol/L)(0.25 mol/L)k = \frac{6.54 \times 10^{-3} \;mol/L\;s}{(0.25 \;mol/L)(0.25 \;mol/L)}k=(0.25mol/L)(0.25mol/L)6.54×10−3mol/Ls
k=0.104 L/mol sk = 0.104 \;L/mol\;sk=0.104L/mols
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