Answer to Question #141626 in General Chemistry for joe

Question

If 10.0 moles of O₂ are reacted with excess NO in the reaction below, and only 6.5 mol of NO₂ were collected, then what is the percent yield for the reaction?
2 NO (g) + O₂ (g) → 2 NO₂ (g)

Answer 1

Calculation of theoretical yield:

n(NO₂) = 2n(O₂) = 20 mol

Proportion:

20 mol – 100 %

6.5 mol – x

$x = \frac{6.5 \times 100}{20} = 32.5$ %

Answer: 32.5 %