Answer to Question #141603 in General Chemistry for Javier

Question

How many grams of AgBr will form when 45.0 mL of 0.842 M CaBr2 react?

CaBr2(aq) + 2 AgNO3(aq) → 2 AgBr(s) + Ca(NO3)2(aq)

Answer 1

 Solution:

Molar mass of AgBr = 187.77 g/mol

mass of AgBr = M of CaBr₂× V of CaBr₂ / 1000ml × n of AgBr × molar mass of AgBr = 0.842molCaBr₂× 45mlCaBr₂/1000ml×2×187.77g/molAgBr = 14.23 g AgBr

Answer: the mass of AgBr is 14.23 g.