Answer to Question #141595 in General Chemistry for Javier

Question

If 2.76 moles of NaCl dissolve in water to make a 900.0 mL solution, what is the molarity of the solution?

Answer 1

number of moles of NaCl = 2.76 moles

Volume = 900mL = $\frac{900}{1000}dm^3 = 0.9dm^3$

$\begin{aligned} \textsf{molarity} &= \dfrac{\textsf{number of moles}}{Volume}\\ \\ &= 2.76/0.9\\ &= 3.07mol/dm^3 \end{aligned}$

$\therefore$ The molarity of the solution is 3.07M