Answer to Question #141157 in General Chemistry for mike

Question #141157
State the order of reaction with respect to a reactant, R, if:
a). the rate of reaction doubles when [R] doubles
b). the rate of reaction is unchanged when [R] triples
c). the rate of reaction reduces by a factor of four when [R] is halved.
1
Expert's answer
2020-11-02T08:47:37-0500

State the order of reaction with respect to a reactant, R, if:


a) the rate of reaction doubles when [R] doubles


b) the rate of reaction is unchanged when [R] triples


c) the rate of reaction reduces by a factor of four when [R] is halved

Solution

 vR=d[R]/dt=k[R]nv_R=-d[R]/dt=k[R]^n - rate equation [1]

a) v1=v2/2v_1=v_2/2 and [R1]=[R2]/2[R_1]=[R_2]/2

Hense 

k[R1]n=k[R2]n/2k[R_1]^n=k[R_2]^n/2

([R1]/[R2])n=1/2([R_1]/[R_2])^n=1/2

n=log[R1][R2]0,5=log120,5=1n=log_{[R_1] \above{2pt} [R_2]}0,5= log_{1 \above{2pt} 2}0,5=1

b) v1=v2v_1=v_2 and [R1]=[R2]/3[R_1]=[R_2]/3

Hence

k[R1]n=k[R2]nk[R_1]^n=k[R_2]^n

([R1]/[R2])n=1([R_1]/[R_2])^n=1

n=log[R1][R2]1=0n=log_{[R_1] \above{2pt} [R_2]}1=0

c)v1=4v2v_1=4v_2 and [R1]=2[R2][R_1]=2[R_2]

Hence

k[R1]n=4k[R2]nk[R_1]^n=4k[R_2]^n

([R1]/[R2])n=4([R_1]/[R_2])^n=4

n=log[R1][R2]4=log24=2n=log_{[R_1] \above{2pt} [R_2]}4= log_{2}4=2

Answer: a) n=1n=1, b) n=0n=0, c) n=2n=2

Reference: https://en.wikipedia.org/wiki/Rate_equation




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