Q141142
According to the following balanced reaction, how many moles of HNO3 are formed from 2.50 moles of NO2 if there is plenty of water present?
3 NO2(g) + H2O(l) → 2 HNO3 (aq) + NO(g)
Solution:
In the question, we are given 2.50 moles of NO2 and there is an excess of H2O, so the ‘moles of HNO3 ‘ formed will depend on the moles of NO2.
The given reaction is
3 NO2(g) + H2O(l) → 2 HNO3 (aq) + NO(g)
In the reaction we can see that the mole ratio of NO2 and HNO3 is
3 mol NO2 : 2 mol HNO3 .
Using this mole ratio we can find the moles of HNO3 formed from moles of NO2 .
Moles of HNO3 formed = 2.50 mol NO2 * 2 mol HNO3/ 3 mol NO2 = 1.6667 mol HNO3 .
In question we are given 2.50 moles of NO2 in 3 significant figures, so our final answer must also be in 3 significant figures.
1.6667 mol HNO3 in 3 significant figure is 1.67 mol HNO3 .
Hence, 1.67 mol HNO3 will be formed from given moles of NO2 and plenty of water.
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