Using the standard enthalpy of formation at 25°C of NO, NO2 and N2O as 90.29KJ/mol, 33.2KJ/mol and 82.05KJ/mol respectively
ΔH=ΔHproducts- ΔHreactants
ΔH= ΔH[2N2O+2NO2] - ΔH[6NO]
ΔH= [(2×82.05)+(2×33.2)] - [6×90.29]
ΔH=164.1+66.4 - 541.74
ΔH= 230.5 - 541.74
ΔH= -311.24KJ/mol
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