The balanced equation for the reaction is "N_2 + 3H_2 \\rightarrow 2NH_3"
"\\therefore" One mole of "N_2" reacts to produce two moles of "NH_3"
1 mole of "N_2" =. 2 moles of "NH_3"
x moles of "N_2" = 0.85 moles of "NH_3"
x = "\\dfrac{0.85 \\times 1}{2}" moles
x = "0.425" moles
"\\therefore \\ 0.425" moles of "N_2" reacted to produce "0.85" moles of "NH_3"
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