Question

How many moles of N2 reacted if 0.85 mol of NH3 is produced?

Answer 1

The balanced equation for the reaction is $N_2 + 3H_2 \rightarrow 2NH_3$

$\therefore$ One mole of $N_2$ reacts to produce two moles of $NH_3$

1 mole of $N_2$ =. 2 moles of $NH_3$

x moles of $N_2$ = 0.85 moles of $NH_3$

x = $\dfrac{0.85 \times 1}{2}$ moles

x = $0.425$ moles

$\therefore \ 0.425$ moles of $N_2$ reacted to produce $0.85$ moles of $NH_3$