Answer to Question #140682 in General Chemistry for Riya

Question

what is the conservation of 1.2 g of NaNO3 dissolved in 80.0 mL of solution

Answer 1

In this context, I think what you wanted to ask is what is the concentration of 1.2 g of NaNO3 dissolved in 80.0 mL of solution

A quick way to calculate concentration is through this formula

Concentration = (mass/molar mass) ×(1000/volume in mL or cm³)

Molar mass of NaNO₃=[23+14+(16×3)]=23+14+48=85g/mol

Concentration= (1.2/85)×(1000/80)= 0.176M

The concentration of the solution is 0.176M