Answer to Question #139887 in General Chemistry for Mary

Question

Silver phosphate, Ag3PO4(s), has Ksp = 8.89 x 10–17. Determine the equilibrium concentration of silver ions in a saturated solution of silver phosphate.

Answer 1

Ksp=[Ag+]^3[PO4^3-]

For every 1 mole silver phosphate dissolved, 3 moles Ag+ will be ionized so plug in 3x for [Ag+]. For [PO4^3-] only 1 mole will ionize so just 1x.

Ksp=[3x]^3[x]

Ksp=27x^4

x=1.82x10^-9.