Given,
Density of the hexane,D = 0.655 g/ml
As we know,
D = (M/V)
Or, M = V×D
So,
mass of (1L=) 1000 ml Hexane
= (1000/0.655) g
= 1526.717 g
Molar mass of Hexane (C6H14)
= (12×6+1×12) g/mol
= 84 g/mol
1L = 1000 ml hexane will have the mass = 1526.717 g
=[ 1526.717 g / 84( g/mol ) ]
= 18.175 mol
As, 1 L of volume contain 18.175 mol of Hexane.
So,
If Hexane is treated as solute of its own , the Molarity of Hexane = 18.175 mol /L
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