Answer to Question #139660 in General Chemistry for Harvey Jed A. Iman

Question

How many mL of 25 M NaOH (sodium hydroxide) is required to react with 50.0 mL of 150 M H2SO4 (sulfuric acid).

Round your answer to 3 decimal places.

Answer 1

The reaction equation:

H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O

The quantity of H₂SO₄:

150 M * 0.050 L = 7.5 mol

So, the quantity of NaOH:

7.5 mol * 2 = 15 mol

The volume of NaOH:

15 mol / 25 M = 0.6 L = 600 mL

Answer: 600 mL