Radioactive decay is characterized by a continuous exponential decay curve given by:
N(t)=Ae−kt
N(t)=Ae−kt
where N(t) is the number of grams of radium present at time t measured in years and A and k are constants. After one half-life, half of the radium remains that was present at t=0. We get:
N(500000)A=12=e−k(500000)
N(1599)A=12=e−k(50000)
ln(12)=−50000
kln(12)=−500000k
k=−1
500000ln(12)
k=−500000ln(12)
k=0.00043349
k=0.00043349
Given at time t=2,000 years there were 5 grams of radium, we can substitute to find A:
5=Ae−0.00043349(2000)
5=Ae−0.00043349(2000)
A=5e0.00043349
(2000)=11.8985
A=5e0.00043349(2000)=11.8985
Now that we have determined the number of grams of radium present at any time t, N
(t)=11.8985e−0.00043349t
N(t)=11.8985e−0.00043349t
, we can calculate the number of grams present at t=5,000 years as follows:
N(500000)=11.8985e−0.00043349(500000)=1.3620
N(5000)=11.8985e−0.00043349(5000)=1.3620
Therefore, 1.36 g of radium remain after 5,000 years rounded to two decimal places.
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