Question

Calculate the mole fraction of each component of a solution containing 65 g of ethanol in 350 g of water.

Answer 1

$\chi (A)=\frac{n(A)}{n(A) + n(B)} * 100$ %

$\chi (H2O)=\frac{m(H2O)/M(H2O)}{m(H2O)/M(H2O) \ +\ m(C2H5OH)/M(C2H5OH)} * 100$ %

$\chi(H2O) = \frac{350/18}{350/18 \ +\ 65/46} * 100$ % = 93.23%

$\chi(C2H5OH) =100$ % - $\chi(H2O)$ = 100%-93.23% = 6.77 %