production 13 gees of C2H2 requires consumption of how many g of H2O
C2H2+2H2O=Ca(OH)2+C2H2
n=mM=1326=0.5n=\frac{m}{M}=\frac{13}{26}=0.5n=Mm=2613=0.5 mol
x2=0.51\frac{x}{2}=\frac{0.5}{1}2x=10.5
x=1
m=n×M=1∗18=18m=n\times M=1*18=18m=n×M=1∗18=18 g
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