Molar mass of SO2 =( atomic mass of Sulphur + 2 X atomic mass of oxygen)
=( 32 + 2 x 16) g/mol
= 64 g/mol
120 grams of SO2 = ( 120 g /64 g.mol )
= (120/64) mol SO2
1 mole of SO2 contain 1 mole of 'S'
(120/64) mole of SO2 contain = (120/64) mole 'S'
= 1.875 mole 'S'
Hence, 1.875 mole 'S' present in 120 grams of SO2.
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