CnH2n+1OH - formula
It's molar mass: 12n+2n+1+16+1= 14n+18
It contains 2n+2 H
The ratio is
2n+2/14n+18 = 12 / mass of alcanol
As we are not given mass of alconol, we substitute it with x
We end up with the equation:
n(x-84)+x=108
It has solutions:
n = 1, x = 96 g, methanol
n = 2, x = 92 g, ethanol
n = 3, x = 90 g, propanol
n = 4, x = 88.8 g, buthanol and so on...
So the mass of the sample is definately requirred to solve the problem :)
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