Question

How many moles are in 40.9 g of titanium(II) chloride?

Answer 1

Given:

titanium(II) chloride - $TiCl_{2}$

mass($TiCl_{2})$ = 40.9 g

Molar mass($TiCl_{2})$ = 118.77 $( \tfrac{g}{mol} )$

Solution:

$n= \dfrac{m}{Mr}$

$n= \dfrac{40.9}{118.77}$

$n=0.344$ moles of TiCl₂