A 1.55 gram sample pf pentanol, C5H11OH is burned and produced a temperature
increase of 55 0 C in 200 g of water. Calculate the heat of combustion of pentanol.
At first, heat absorbed by water should be calculated.
Q=cm∆T, where c is a specific heat of water.
Q=4.184×200×55=46024(J).
It is equal (but with opposite sign) to heat released during combustion.
Q=-46024 J = -46.024 kJ.
To find molar heat of combustion this number should be divided into a mass of pentanol and multiplied by it's molar mass.
M=5×12+12×1+1×16=88(g/mol).
Q=-46.024×88/1.55=-2612.975(kJ).
Comments
Leave a comment