Question

In the laboratory you dissolve 16.3 g of iron(III) bromide in a volumetric flask and add water to a total volume of 375 . mL.

What is the molarity of the solution?

Answer 1

Iron II Bromide$= FeBr_3$ Molar mass of= $295.56 g/mol$

$moles = 16.3 g \times \frac{1 mol}{295.56 g} = 0.056moles$

liters of the solution = 375 ml x 1 L/1000 ml = 0.375 L

$Molarity=\frac{Moles}{Volume}=\frac{0.056}{0.375}=0.147M$