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Answer to Question #135740 in General Chemistry for Austin
Question #135740
How many moles of CaCO3 are formed from 35.08g of CaO
Expert's answer
CaCO3 ---- CaO +CO2
1 mole of CaCO3----100grams
100g of CaCO3-- 56 g of CaO
--- 35.08g
(35.08×100)÷56=62.64 grams of caco3
1 mole of caco3 =100 grams
? =62.64 grams
(62.64×1)÷ 100= 0.63 moles
=0.63 moles.
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