Answer to Question #135703 in General Chemistry for Burqa

Question

A water sample was tested and was found to contain ions of two varieties. Ion A is a smaller positive ion compared to ion B. When paired with CO3-2, the salt formed with A is having a ratio of 1:1, while for B, the anion-cation ratio is 1:2. This result was comparable to the pair of potassium sulfate and barium sulfate, and to that of lead (II) sulfate and lead (IV) sulfate.

1) Explain the differences between the pairs of compounds given (potassium sulfate and barium sulfate/ lead (II) sulfate and lead (IV) sulfate). These both exhibit 1:1 and 1:2 anion-cation ratios.

Answer 1

In both the compounds are made up of captions and anions.however, in the ion A it has a lower valency than ion B ,the ion A has the same valency as the carbonate anion hence the ratio between the two becomes 1:1 similar to barium sulphate ,while in ion B the ratio of the anion -cation is 1:2 due to the difference in valencies. Similar to potassium sulphate ,where potassium has a valency of 1 and the sulphate has a valency of 2 ,in the combination of forming the compound , elements Change valencies.