A water sample was tested and was found to contain ions of two varieties. Ion A is a smaller positive ion compared to ion B. When paired with CO3-2, the salt formed with A is having a ratio of 1:1, while for B, the anion-cation ratio is 1:2. This result was comparable to the pair of potassium sulfate and barium sulfate, and to that of lead (II) sulfate and lead (IV) sulfate.
Questions/Tasks
1) Explain the differences between the pairs of compounds given (potassium sulfate and barium sulfate/ lead (II) sulfate and lead (IV) sulfate). These both exhibit 1:1 and 1:2 anion-cation ratios.
2)Assuming that A and B are representative elements show the electron transfer and give the formulas of the compounds formed for both cations using the following anions: Br- and S-2. Explain the reason for such electron transfer.
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Expert's answer
2020-09-28T14:29:24-0400
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