A water sample was tested and was found to contain ions of two varieties. Ion A is a smaller positive ion compared to ion B. When paired with CO3-2, the salt formed with A is having a ratio of 1:1, while for B, the anion-cation ratio is 1:2. This result was comparable to the pair of potassium sulfate and barium sulfate, and to that of lead (II) sulfate and lead (IV) sulfate.
Questions/Tasks
1) Explain the differences between the pairs of compounds given (potassium sulfate and barium sulfate/ lead (II) sulfate and lead (IV) sulfate). These both exhibit 1:1 and 1:2 anion-cation ratios.
2)Assuming that A and B are representative elements show the electron transfer and give the formulas of the compounds formed for both cations using the following anions: Br- and S-2. Explain the reason for such electron transfer.
1
Expert's answer
2020-09-28T14:29:24-0400
Dear Burqa, your question requires a lot of work, which neither of our experts is ready to perform for free. We advise you to convert it to a fully qualified order and we will try to help you. Please click the link below to proceed: Submit order
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment