Answer to Question #135656 in General Chemistry for Lois An Macalalad

Question

90 The solvent dichloromethane (CH2Cl2, molar mass 84.93 g /mol) can be prepared by reaction of methane (CH4, molar mass 16.04 g/mol) with (Cl2 molar mass 17.90 g/mol), according to the balanced equation CH4 + 2CL2  CH2Cl2 + 2HCl.
A. If 5.00 g of methane and 15.0 g of cl2 are used, how many moles of each reactant are used?
B. What is the limiting reactant?
C. How many grams of products are formed?
E. If 5.6 g of product are formed, what is the percent yield of the reaction?

Answer 1

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