Answer to Question #135610 in General Chemistry for Justin Derouchie

Question

If the yield from the reaction of acetic acid with isopentyl alcohol is 45%, how many grams of isopentyl acetate are formed from 3.68 g of acetic acid and 4.69 g of isopentyl alcohol? The reaction is:
CH3CO2H+C5H12O→C7H14O2+H2O

Answer 1

Given reaction

CH3CO2H+C5H12O→C7H14O2+H2O

from the given reaction 1 mole of acetic acid reacts with 1 mole of isa pentyl alcohol to produce 1 mole of isopentyl acetate.

Hence theoretical yield of the above reaction =( number of product produced/number of reactant involved)

= 1

Molar mass of acetic acid = 48 g/mol

So, 3.68 grams of acetic acid = 3.68 g ÷ 48 g/mol

≈ 0.077 mole

Molar mass of isopentyl alcohol = 88 g/mol

So, 4.69 g of isopropyl alcohol =4.69 g ÷ 88g/mol

≈ 0.0533 mole

Hence, theoretically, 0.0533 moles of isopentyl alcohol will react with the 0.0533 moles of acetic acid to produce 0.0533 moles of isopentyl acetate = (0.0533 × molar mass of isopentyl acetate) g

= (0.0533× 130)g

= 6.929 g

We know percentage (%) of yield = (observed yield ÷ theoretical yield) × 100 %

So, observed yield =( percentage of yield x theoretical yield) ÷ 100 g

Given,

Percentage of yield = 45%

And theoretical yield we obtained = 6.929 g

So, observed yield =[(45 × 6.929 )÷ 100] g

= 3.118 g

Hence, 3.118 grams of isopentyl acetate will be produced from the given amount of reactants.