Answer to Question #134430 in General Chemistry for Aaliyah

Question

the mass, in grams, of magnesium nitrate that must be added to a 300-mL volumetric flask in order to prepare 300 mL of a 0.234 M aqueous solution of the salt.

Answer 1

Ans.

Molecular weight of magnesium nitrate = 148.32 gm

1000 ml 1M magnesium nitrate = 148.32 gm

300 ml 0.234 M magnesium nitrate = [(148.32 x 0.234 x 300)/(1000)] gm = 10.41 gm

10.41 gm of magnesium nitrate that must be added to a 300-mL volumetric flask in order to prepare 300 mL of a 0.234 M aqueous solution of the salt (Ans.)