QUESTION # 132910
A 2.000 g piece of copper was used to precipitate silver ions aa silver solution. When the copper metal reacts, Cu2+ ions are formed which are soluble in water. If 0.750 g of Ag(s) were produced in this process what should the final mass of the copper wire be?
ANSWER
Equation for the reaction
Cu(s) +2Ag+(aq) ͢ Cu+2(aq) + 2Ag(s)
Moles of Ag formed =0.750/107.868
= 0.006953 mol
Moles of Cu used = ½ (0.006953) mol
= 0.0034765 mol
Mass of Cu used = 0.0034765×63.546
= 0.2209g
Final mass of Cu wire = 2.000-0.2209
= 1.779g
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