Question

What is the mass (in g) of a sample of SF4 that contains 5.5E+23 fluorine atoms?

Answer 1

Solution:

1) Let's calculate the number of moles of fluorine:

Moles of fluorine = n(F) = 5.5×10²³ atoms × (1 mol / 6.022×10²³ atoms) = 0.9133 mol

2) Let's calculate the number of moles of SF₄:

Schematic equation: SF₄ --> 4F

n(SF₄) = n(F) / 4 (according to the equation)

n(SF₄) = 0.9133 mol / 4 = 0.2283 mol

3) Let's calculate the mass of a sample of SF₄:

Moles of SF₄ = Mass of SF₄ / Molar mass of SF₄

The molar mass of SF₄ is 108.07 g/mol.

Thus:

Mass of SF₄ = Moles of SF₄ × Molar mass of SF₄ = (0.2283 mol) × (108.07 g/mol) = 24.67 g

The mass of a sample of SF₄ is 24.67 g.

Answer: The mass of a sample of SF₄ is 24.67 g.