If 1 mole of nitrogen has 6.023× 10^23 atoms then 9.23×10^-2 moles will have ;
(9.23×10−2)×(6.023×1023)÷1{(9.23×10^-2) × (6.023×10^23)}÷1(9.23×10−2)×(6.023×1023)÷1= 5.56×10^22 atoms
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