Answer to Question #131527 in General Chemistry for tumi

Question

what is the equilibrium constant for the expression of the reaction
3Fe + 4H2O =Fe3O4 + 4H2

Answer 1

Equilibrium constant( $K_{eq}$ ) is an expression of a relationship between the amounts of products and reactants i n a chemical reaction at equilibrium.

For a general reaction,

$cC\ +dD\ =\ eE\ + \ fF$

equilibrium constant is expressed as follows;

$K_{eq}=\dfrac{[E]^e[F]^f}{[C]^c[D]^d}$

Therefore, in the following reaction,

$3Fe\ + \ 4H_2O\ =\ Fe_3O_4\ +4H_2$

the equilibrium constant is

$K= \dfrac {[Fe_3O_4]\ [H_2]^4}{[H_2O]^4[Fe]^3}$