Question

Build a voltaic cell with one beaker containing potassium permanganate (KMnO4) solution with a platinum electrode and a second beaker containing zinc chloride with a zinc electrode. Determine

a. The half reactions

b. Flow of electrons

c. Short-form notation

d. Electric potential (voltage)

Answer 1

a. Zn+2Cl^-=ZnCl₂+2e^-

Pt(MnO4)₂+2e^-=Pt²⁺+2MnO4^-

b. Zn= Zn²⁺ + 2e^-

Pt= Pt²⁺ + 2e^-

Zn + Pt ²⁺ → Pt+ Zn²⁺

c.

Zn(s) ZnCl₂ (s) Cl- (aq) Pt(MnO₄)₂(s) Pt(MnO₄₎(s) Pt(s)

d. ϕ(Zn)=-0.763 B

ϕ(Pt)=+1.19 B

0.763+1.19=1.953 B