Question #131358
How many moles of HCl are present in 40 mL of a .035 M solution?
1
Expert's answer
2020-09-01T07:36:08-0400

Number of moles== Molarity ×\times Volume ( in Litres)

Volume (V)=40 ml=401000 L=0.04 L( V) = 40\ ml = \frac{40}{1000} \ L= 0.04 \ L

Molarity (M)=0.35 M( M) = 0.35\ M

Number of moles =0.04×0.35=0.014=0.04\times 0.35=0.014


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