Given that : In 1 yr the mass of nitrogen in liquid (river) is 2.558×1072.558×10^72.558×107 mg,
and the volume of liquid is V=4.02×108LV = 4.02×10^8 LV=4.02×108L
concentration =mass(mg)volume(L)=2.558×1074.02×108\frac{mass(mg)}{volume(L)}= \frac{2.558×10^7}{4.02×10^8}volume(L)mass(mg)=4.02×1082.558×107
=0.557mg/L=0.557mg/L=0.557mg/L
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